How do i sort a string array in alphabetical order?

[HaifaCarina]

these are the loops i used:

for (h = 0; h<name.length;h++)
          {
            highestOrder [h] = Integer.valueOf(name[h].charAt(0));
         	highestName [h] = name[h];
            for (int count = 0; count<name.length;count++) {

	            if (Integer.valueOf(name[count].charAt(0)) < highestOrder[h])
	            {

	                highestOrder[h] = Integer.valueOf(name[count].charAt(0));
	                temporary = Integer.valueOf(name[h].charAt(0));
	                
	                Integer.valueOf(name[h].charAt(0))= Integer.valueOf(name[count].charAt(0));
	                Integer.valueOf(name[count].charAt(0))= temporary; 
	                	
	                
	                highestName[h] = name[count];
	                tmp = name[h];
	                name[h] = name[count];
	                name[count] = tmp;
	
	            }
	         }
          }
	     for (int count=0; count<name.length;count++)
         {
           	 System.out.println(highestOrder[count] + " ");
             System.out.println(highestName[count] + " ");
         }

here's the part with the error:

	               
temporary = Integer.valueOf(name[h].charAt(0));
Integer.valueOf(name[h].charAt(0))= Integer.valueOf(name[count].charAt(0));
Integer.valueOf(name[count].charAt(0))= temporary;

and i can't find a way how to substitute it or anything..or is there any simplified way to sort string arrays in alphabetical order? i really need help...

[JosAH]

Better use the Arrays.sort() method; or do you have to sort the elements in
your array yourself? Is it homework?

kind regards,

Jos