small windows code snippet to enable Wireless LAN and disable Wireless LAN

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  • tvnaidu
    Contributor
    • Oct 2009
    • 365

    small windows code snippet to enable Wireless LAN and disable Wireless LAN

    I am looking on Internet , I couldn't find, small windows code snippet to enable Wireless LAN and disable Wireless LAN or small dialog to enable / disable wireless LAN.thanks.
  • mubasharAhmad
    New Member
    • Feb 2016
    • 1

    #2
    I am looking on Internet , I couldn't find,

    Comment

    • tvnaidu
      Contributor
      • Oct 2009
      • 365

      #3
      Thanks a lot. wrote simple app - I need to run this app as "Run as administrator" mode, when I am regular user and no admin password with me, I canot run this.

      Code:
      using System;
      using System.Collections.Generic;
      using System.ComponentModel;
      using System.Data;
      using System.Drawing;
      using System.Linq;
      using System.Text;
      using System.Threading.Tasks;
      using System.Windows.Forms;
      
      namespace WindowsFormsApplication2
      {
          public partial class Form1 : Form
          {
              public Form1()
              {
                  InitializeComponent();
              }
      
              private void button1_Click(object sender, EventArgs e)
              {
                  System.Diagnostics.Process process = new System.Diagnostics.Process();
      
                  MessageBox.Show("WLAN Enable");
                  process.StartInfo.FileName = "net.exe";
                  process.StartInfo.Arguments = "start Wlansvc";
                  process.Start();
                  
              }
      
      
              private void button2_Click_1(object sender, EventArgs e)
              {
                  System.Diagnostics.Process process = new System.Diagnostics.Process();
                  MessageBox.Show("WLAN Disable");
                  process.StartInfo.FileName = "net.exe";
                  process.StartInfo.Arguments = "stop Wlansvc";
                  process.Start();
              }
      
          }
      }

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