how to skip the value in printf in c

[sravanthichinta]

#include<stdio. h>
void main()
{
int i=6;
printf("%d %*d\n",i,i+9);
}
what is the out put?

[donbock]

What happens is undefined behavior. The call to printf doesn't have enough arguments.

Refer to man page for printf. The format string has two format specifies: "%d" and "%*d"; the first expects one argument and the second expects two arguments. Thus, three arguments should follow the format string but you only have two.

[mukherjee]

It will most likely crash.