I need help to limit the loop into the next 4 interations

[HazenZero]

I have a user input, and I need the loop to continue for the next 4 iterations of the user input. I have no idea how because everytime I try to do it, it becomes either and infinite loop or just crashes.. Please help

#include <stdio.h>

int main ()
{
	double H, t;
	double a, b;

	a = 2.13;
	b = 0.05;
	
	printf("Please enter input fot t:");
	scanf("%lf", &t);
	
	H = ((a * t)*(a * t))-((b * t)*(b * t)*(b * t));
	
	if (H > 100)
	{
		printf("\nHigh\n");
	}
	else if (H > 50)
	{
		printf("Average\n");
	}
	else 
	{
		printf("Low\n");
	}
	
	printf("\nt\t\t   H\n");
	printf("----------------------\n");
	
	for (t=t; t < (t + 5); t++)
	{
		H = ((a * t)*(a * t))-((b * t)*(b * t)*(b * t));
		printf("%.0f\t\t%.2f\n", i, H);
		
	}

	return 0;
}

[Banfa]

t < (t + 5) will always be true by definition.

Think of any number, add 5 to it. Is the result greater than the original number?

You need to use 2 variables, t, which you increment and another variable that you set up before the loop starts to contain the end point for the loop.

max = t + 5;
for( ; t < max; t++)
{
  ...
}

[donbock]

Is your intent to loop through your program a fixed number of times? If so, then I wouldn't use user input t as a loop variable. Better to add a separate variable whose only purpose is to control the loop.

int i;
for (i=0; i<5; i++)
{
   ...
}

By the way, it is unusual to use a floating point variable (t) to control a loop.