How do I convert this pseudocode to C++?

[DrewDroid]

Can someone please help me convert some of this code to C++? It would be greatly appreciated.

int __cdecl sub_401000(int a1, int *a2)
{
  int v2; // ebx@1
  int v3; // eax@1
  int v4; // eax@1
  int v5; // eax@2
  int result; // eax@2
  int v7; // [sp+10h] [bp-Ch]@1
  int v8; // [sp+14h] [bp-8h]@1

  v2 = a1;
  v8 = (int)"D:hhMessage.h";
  v7 = 156;
  v3 = sub_660A30((int)&a1, 0);
  v4 = sub_65FD30(0x14u, (int)&v7, *(_DWORD *)v3);
  if ( v4 )
  {
    v5 = sub_116EE20(*a2, v4);
    sub_4010E0(v2, v5);
    result = v2;
  }
  else
  {
    sub_4010E0(v2, 0);
    result = v2;
  }
  return result;
}

int __thiscall sub_4011F0(void *this)
{
  void *v1; // esi@1
  int result; // eax@1

  v1 = this;
  result = (int)((char *)this + 4);
  if ( !_InterlockedExchangeAdd((signed __int32 *)this + 1, 0xFFFFFFFFu) )
  {
    result = (*(int (__thiscall **)(_DWORD))(*(_DWORD *)this + 4))(this);
    if ( !_InterlockedExchangeAdd((signed __int32 *)v1 + 2, 0xFFFFFFFFu) )
      result = (*(int (__thiscall **)(_DWORD))(*(_DWORD *)v1 + 8))(v1);
  }
  return result;
}
---------------------------------------------------------
bool __stdcall sub_63DE40(int a1)
{
  return a1 == (_DWORD)"Msg_Dig";
}

int __userpurge sub_4284D0<eax>(int a1<eax>, int a2)
{
  int result; // eax@1
  int v3; // ecx@2
  int v4; // ecx@3
  int v5; // esi@3
  char v6; // [sp+10h] [bp-8h]@1
  int v7; // [sp+14h] [bp-4h]@3

  result = sub_428B50((int)&v6, a1);
  if ( result != a2 )
  {
    v3 = *(_DWORD *)result;
    *(_DWORD *)result = *(_DWORD *)a2;
    *(_DWORD *)a2 = v3;
  }
  v4 = *(_DWORD *)(a2 + 4);
  *(_DWORD *)(a2 + 4) = *(_DWORD *)(result + 4);
  *(_DWORD *)(result + 4) = v4;
  v5 = v7;
  if ( v7 )
  {
    result = v7 + 4;
    if ( !_InterlockedExchangeAdd((signed __int32 *)(v7 + 4), 0xFFFFFFFFu) )
    {
      result = (*(int (__thiscall **)(int))(*(_DWORD *)v5 + 4))(v5);
      if ( !_InterlockedExchangeAdd((signed __int32 *)(v5 + 8), 0xFFFFFFFFu) )
        result = (*(int (__thiscall **)(int))(*(_DWORD *)v5 + 8))(v5);
    }
  }
  return result;
}

If some of this is too hard, then I understand. You don't have to convert it if you don't want to.

[weaknessforcats]

I can provide assistance in areas where you are stuck or I can provide advice on how to proceed in a given situation. However, I do not provide code, write specs, etc.

In any case, this does not look like pseudo code so I am not sure exactly what it is you are asking.