error 'for' loop initial declaration used outside c99 mode

[Aloasch]

i have this error while compiling the programm.

Below is the code and thank zou in advance ;)

#include<stdio.h>
#include<stdlib.h>


int main()
{
    char* A = 0;
    char* tmp = 0;
     size_t size =0;
     char c = 0;
    while((c = fgetc(stdin)) != EOF)
    {
         size ++;
        tmp = (char*)malloc(size);
        A = (char*)realloc(A,size); 
        A[size-1] = c; 
        free(tmp);
    }

      for( size_t i=size ;i>0;i--)
    {
        printf("%c",A[i]);
    }
    printf("\n");
    free(A);
   
   return 0;
}

[Banfa]

Line 20 you declare i as a size_t as part of your loop, C++ allows this and I think C99 allows this but it sounds like you are using a C89 compiler (that is C99 aware) and it doesn't allow this syntax.

Declare i at the top of the function along with all the other variables (lines 7-10).

[donbock]

By the way, in line 11 you set c to the return value of fgetc. c is a char, but fgetc returns an int. Whether EOF fits in a char is compiler dependent. Your code will be more reliable if c were an int. Making this change may provoke some new type warnings that you will have to resolve.