How to set each bit, if the variable is short

[jtnshah]

i am using the below logic. but it gives me error when i am setting the bit_position 15 or 16. i suspect, the problem with the integer range.
please suggest.

short bit_map, bit_position

bit_map = bit_map | ( 1 << bit_position )

[weaknessforcats]

A sort is 16 bits. Shifting 1 left by 16 bits won't work because the short is too small. Shifting 1 left 15 bits destroys the short's sign bit. Since most negative values are stored in 2's complement form, a 1 in the sign bit will cause the value t appear as a very large negative number. But you can avoid the sign bit problem by using an unsigned short.

[liamtosurvive]

I think U can use ':'the do this!