double wil not display correct value's.

[Paul Jelis]

if I load a double number

VALUE=123456789;
printf("%f \n",VALUE); // give's 123456789
VALUE=138414/1000000;
printf("%f \n",VALUE); // gives me 0.000000000

I want to add a number + some decimal

VALUE[0]=12345678;
VALUE[1]=.138414;
VALUE[2]=VALUE[0]+VALUE[1];
I don't get the expected  12345678.138414

wat's wrong here ?

[weaknessforcats]

This code:

VALUE=138414/1000000;

gives a value of 0. 138414/1000000 is zero. These are ints and 1000000 goes into 138414 zero times.

This code:

VALUE[0]=12345678;
 VALUE[1]=.138414;
 VALUE[2]=VALUE[0]+VALUE[1];

appears to work OK but are you displaying VALUE or VALUE[2] ?

If you are inadvertantly displaying VALUE you will see 0.0 because VALUE is an address (the name of an array is the address of the array).