Code:
void main()
{
char a, *b, c[3];
a= 0xaa;
b = &a;
c[0]= a;
c[9] = *b + 10;
c[1] = *(c+9)++;
*c = *b--;
printf(“%s\n”,c);
}
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Last edited by Banfa; Jan 23 '12, 02:17 PM. Reason: Use code tags, next time don't just post code. Post you question and a complete listing of any compiler errors. -
Line 8: (c+9) is a pointer and you can't apply the increment operator to a pointer. Did you mean (*(c+9)++?
Among other errors in your program
1. Line 1: main returns int not void
2. Line 4: 0xaa is greater than the value you can store in a signed char
3. Line 7: c[9] is out of range for the array c which only has a size of 3 and therefore valid indexes 0, 1, 2
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