what is the output?

[saraswathi v]

char ch="name";printf("%d%c",53815);

[horace1]

although the program may compile and run it has a couple of errors

char ch="name";

ch is a char (a byte sized int)and you are attempting to initialise it with the address of a string (a pointer) so you would get a compiler message such as (from gcc)

warning: initialization makes integer from pointer without a cast

the printf statement

printf("%d%c",53815);

has two conversion specifications %d and %c but only one parameter following. The %d would print 53815 as an int and the %c would pick whatever is next on the stack and print it as a char.