What is the output of following code?

[vensriram]

#define EXMP 25
main ( )
{ int exmp = 35;
printf (“\nvalue of exmp is %d”,EXMP);
}

my answer is 35
Is it correct?

[Oralloy]

Why do you think 35 is the correct answer?

[vensriram]

In C the IDENTIFIERS are case sensitive. Hence I think the same applies here? Is it ok

[Oralloy]

Not only are identifiers case sensitive, but keywords are as well.

In this case, you also have a macro, which modifies the source code before the compiler even gets ahold of it. Your code after preprocessing is equivalent to:

main ( )
{ int exmp = 35;
printf (“\nvalue of exmp is %d”,25);
}

Observe that the definition is erased and the token EXMP is replaced with the value from the definition.

Hopefully that helps a little.

Cheers!

[vensriram]

yes u r correct

Thanks Oralloy...

[Oralloy]

You're welcome, vensriram.

Cheers!