char * in array of int

[noob15]

	int aa[3]={300,3,4};
	char *p;
	p=aa;
	p=(char*)((int *)(p));
	printf("%d",*p);
	p=(int*)(p+1);
	printf(" %d",*p);
	p++;
	printf(" %d",*p);

output :: 44 1 0

can someone help me with why this output is coming (especially 1 after 44)

[Banfa]

It is probable that line 4 of you code does nothing.

As to the values you are getting consider the individual value of the bytes in each integer.

[noob15]

It is probable that line 4 of you code does nothing.

As to the values you are getting consider the individual value of the bytes in each integer.

means is it like this

a[0] = 00000000 00000000 00000001 00101100

since my linux x86 architecture uses little-endian it is stored as 00101100 00000001 00000000 00000000

means answer will be different in case of Big-endian ??

[Banfa]

Yes .