how to give typedef for a function pointer?

[bajajv]

Hi,
I want to typedef a function pointer, but getting some errors.

This is the code:

#include <stdio.h>
typedef ((int) (*) (int, int)) Callback;
Callback cb; 

int add(int i, int j) 
{return (i+j);}

int main()
{ cb = &add;
  int res;
  res = cb(10, 20);
  printf("%d", res);
  return 0;
}

How to give this typedef statement?

[Banfa]

The thing to remember with typedefs is the type name goes exactly where the variable name goes if you where creating a variable of that type.

Of course that doesn't help if you don't know how to create pointer to function variable. What you are actually creating is a pointer, the return type and parameter list just modify the pointer so the variable (or type name) go next to the *.

typedef int (*Callback)(int , int);

[bajajv]

Got the point.. thanks.. :)