how is size of pointer calculated?

[ycoerohan]

char *ptr;

sizeof(*ptr) will return you 1 (size of char varaible whose address it can hold).

char *ptr[10];

sizeof(*ptr) will return you 4 why???

Please clear my doubt regarding pointer

[Banfa]

char *ptr[10] is an array of 10 pointers to char.

*ptr, as with any array is equilivent to the first member of the array, ptr[0]. Since ptr is an array of 10 pointers to char ptr[0] is a pointer to char (char*) so *ptr is a pointer to char (char*).

Therefore sizeof(*ptr) == sizeof(ptr[0]) == sizeof(char *) which on you machine (which I assume is a 32bit machine) is 4 bytes.