how do I access a member class of a class template from a template child class

[presencia]

Hi all,
I got the following problem. I have two class templates, one inheriting from the other.

template<typename T>
struct M{
	class A{};
};

template<typename T>
class B:public M<T>{
	A a;
};

I know that this code is not correct. I've read about the compiler's two-phase lookup of members in template classes. So I assume that giving the fully qualified name would work. But it doesn't: If I replace the

A a;

with

M<T>::A a;

the compiler (gcc 4.4.3) complains about this line with

error: ISO C++ forbids declaration of ‘A’ with no type
error: expected ‘;’ before ‘a’

My questions are:
1. Is there any way to use the A class in my B class?
2. I have read that for non-type members of the class template M I can use the "using" declaration inside the child class to be able to use it like its own member. Is there anything I like this for type-members like class A?
I would gratefully appreciate any help.
~<><~~~~~~~ presencia

[Banfa]

The problem is that because M is a template class the compiler can not tell what type of thing M<T>::A is and assumes it is a symbol. You need to tell the compiler it is a type name like this

template<typename T>
class B: public M<T>{
    typename M<T>::A a;
};

[presencia]

Thanks Banfa,
I don't know why I didn't try just this before. It works, thank you. This thread is solved.
~<><~~~~~~~ presencia