String output functions dilemma....

[abhinuke]

OK,so I am working on this code in which I have to enter a string of length 20.After which I will enter a value of variable n resulting into output string which will start from index n upto white space or end of line.

For ex:-if I enter string as John Smith and n=0 then it should output string as John and if n=2 then ohn.

I tried to code this program in C/C++ but vain.Segmentati on faults is the only result that I am getting.

Here is the code that I am working on.

#include <stdlib.h>
#include<string>
#include<iostream>
#include<ctype.h>
using namespace std;
int main()
{
    char a[20];
    int i,n;
    cout<<"Enter the desired string";
    cin.getline(a,20);
    cout<<"Enter string number\n";
    cin>>n;
    
    if(n==0)
    {
        cout.write(a,20);
    }
    else
    {
        
        cout<<"The required string is \n";
        i=n;
        while(a[i]!=' '||a[i]!='\0')
        {
            cout<<a[i];
            i++;
        }
    }

    return 0;
}

I am also confused between cin and cin.getline functions.Sugge stions,hints are welcome.

Thanks in advance.
Cheers.

[Dheeraj Joshi]

Few modification for your while loop. Is it necessary to check a[i]!=' ' in this loop? Why you want it? And you must check the index has not crossed 20(Since you have a character array of size 20).

while((a[i]!=' '|| a[i]!='\0') && i < 20)
        {
            cout<<a[i];
            i++;
        }

Regards
Dheeraj Joshi

[abhinuke]

Few modification for your while loop. Is it necessary to check a[i]!=' ' in this loop? Why you want it? And you must check the index has not crossed 20(Since you have a character array of size 20).

while((a[i]!=' '|| a[i]!='\0') && i < 20)
        {
            cout<<a[i];
            i++;
        }

Regards
Dheeraj Joshi

@dheerajjoshim

Thanks...that worked fine......Cant believe I am forgetting counters these days...

[Dheeraj Joshi]

Happens in software development environment. :)

Regards
Dheeraj Joshi