Have a problem in finding the output of an program.

[AnagJohari]

int main()
{
    unsigned int m = 32;
    printf("%x\n", ~m);
    return 0;
}

where int is 32 bits
can u explain how the 32 stored in a memory
according to me:-
-------------------
binary no-100000
here is only 6 bit
can u explain the representation of "32" in 32 bits form in a memory

by the way the ans of this :-ffdf

please explain why this ans comes

[Dheeraj Joshi]

In 6 bit 32 looks like 100000
In 32 bit it looks like (0)000000000000 000000000000010 0000

Where 0 within the ( ) indicates the sign bit.

And output must be

ffffffdf

~ operator does the bitwise complement(1's complement). i.e all the bits in an expression will be flipped.

Regards
Dheeraj Joshi

[AnagJohari]

In 6 bit 32 looks like 100000
In 32 bit it looks like (0)000000000000 000000000000010 0000

Where 0 within the ( ) indicates the sign bit.

And output must be

ffffffdf

~ operator does the bitwise complement(1's complement). i.e all the bits in an expression will be flipped.

Regards
Dheeraj Joshi

can u reply in stepwise way how this ans comes..

[donbock]

You should familiarize yourself with the bitwise operators. (Notice that the referenced article is about the operators, not how to express them in any particular computer language.)

You should familiarize yourself with two's-complement representation of binary numbers. The C Standard does not mandate two's-complement representation, but that is by far the most common representation. It is clear from the "correct answer" that your machine uses two's-complement.