How The Address or Value Access from 3D array using pointers?

[AnagJohari]

main( )
{
  int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}};
printf("%u %u %u %d \n",a,*a,**a,***a);
printf("%u %u %u %d \n",a+1,*a+1,**a+1,***a+1);
 	 }

If the location of an array start from 100.

can you please explain all this by giving the demonstration of how the location is saved from one to other & how the location & the value is access please explain in detail.
Thank you

[Banfa]

You might want to start by running the code and seeing if you can explain it.

As a tip it may (or may not) help if all the values in the array have different values so you can easily differentiate them.

[weaknessforcats]

You might also read this article: http://bytes.com/topic/c/insights/77...rrays-revealed.

There is a lot of info here about how arrays actually work.

[donbock]

You are using %u (unsigned int) to print [some] pointer values. Are you sure int is wide enough on your platform?

I suggest changing your array declaration from int to unsigned long and then using conversion specifier "%lu". Unsigned long isn't guaranteed to be wide enough to hold a pointer value either, but from a practical point of view it is good enough.