How do i convert an alphabetic phone number to a numeric phone number?
Translating alphabetic number:
Enter phone number:1-800-COL-LECT
1-800-265-5328
Translating alphabetic number:
Enter phone number:1-800-COL-LECT
1-800-265-5328
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Simplest way is create an array and assign each letter it's corresponding number. Then loop through the phone number input and replace the letter with number.niheel @ bytes -
Uhmm....I think:
if string s=1800-COL-LECT
If(s[i]=='-') write nothing
else ii(s[i]>==0 || s[i]<==9)write s[i]
if(s[i]=='A'||s[i]=='B'||s[i]=='C')write 2
etc for DEF,GHI,JKL,MNO ,PQRS,TUV and WXYZ.Comment
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I suggest using <ctype.h> classification functions isdigit() and isalpha(). You probably want to treat 'a' the same as 'A'. Instead of the logical expression in the if statement, I suggest using a switch statement -- it will be easier to read:
Code:switch (toupper(s[i])) { case 'A': case 'B': case 'C': s[i] = '2'; break; ...Comment
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hi..sorry i don't really understand how to convert and store and show all number back...can u please show more details of code...i am really new to c programmingComment
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can u show me some example code?in more details pls..Comment
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Refer to the posting guidelines.
We'll answer questions like "why did I get this error?"; we won't answer questions like "I don't know how to start, please send me the code."Comment
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so this is some code i have done...but i duno how to make it...store and display back...is it using for loop n strlen?Code:#define SIZE 30 void translateNumber(int * optionStats, char * phoneNumber) { char phoneNumber[SIZE]; int x=0; int length; printf("Translating alphatic number:\n"); printf("Enter Phone Number:\n"); while (fgets(phoneNumber, SIZE, stdin) != NULL) /* fetch up to 30 chars */ { switch (toupper(phoneNumber[x])) { case 'A': phonenumber[x]="2"; break; case 'B': phonenumber[x]="2"; break; case 'C': phonenumber[x]="2"; break; case 'D': phonenumber[x]="3"; break; case 'E': phonenumber[x]="3"; break; case 'F': phonenumber[x]="3"; break; case 'G': phonenumber[x]="4"; case 'H': phonenumber[x]="4"; case 'I': phonenumber[x]="4"; case 'J': phonenumber[x]="5"; case 'K': phonenumber[x]="5"; case 'L': phonenumber[x]="5"; case 'M': phonenumber[x]="6"; case 'N': phonenumber[x]="6"; case 'O': phonenumber[x]="6"; case 'P': phonenumber[x]="7"; case 'Q': phonenumber[x]="7"; case 'R': phonenumber[x]="7"; case 'S': phonenumber[x]="7"; break; case 'T': phonenumber[x]="8"; break; case 'U': phonenumber[x]="8"; break; case 'V': phonenumber[x]="8"; break; case 'W': phonenumber[x]="9"; break; case 'X': phonenumber[x]="9"; break; case 'Y': phonenumber[x]="9"; break; case 'Z': phonenumber[x]="9"; break; }
any tips? thanks alotComment
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Read the threads above. .
Essentially you have converted the alphanumeric number to numeric. Now print it
using a for loop.
To improve your code you can group cases 'A','B'and'C' as suggested in thread #4Comment
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is it correct way to print?
please correct me if i m wrong...thanks. ..
Code:#define SIZE 30 void translateNumber(int * optionStats, char * phoneNumber) { phoneNumber[SIZE]; int x=0; int length; printf("Translating alphatic number:\n"); printf("Enter Phone Number:\n"); while (fgets(phoneNumber, SIZE, stdin) != NULL) /* fetch up to 30 chars */ { switch (toupper(phoneNumber[x])) { case 'A': phoneNumber[x]="2"; break; case 'B': phoneNumber[x]="2"; break; case 'C': phoneNumber[x]="2"; break; case 'D': phoneNumber[x]="3"; break; case 'E': phoneNumber[x]="3"; break; case 'F': phoneNumber[x]="3"; break; case 'G': phoneNumber[x]="4"; case 'H': phoneNumber[x]="4"; case 'I': phoneNumber[x]="4"; case 'J': phoneNumber[x]="5"; case 'K': phoneNumber[x]="5"; case 'L': phoneNumber[x]="5"; case 'M': phoneNumber[x]="6"; case 'N': phoneNumber[x]="6"; case 'O': phoneNumber[x]="6"; case 'P': phoneNumber[x]="7"; case 'Q': phoneNumber[x]="7"; case 'R': phoneNumber[x]="7"; case 'S': phoneNumber[x]="7"; break; case 'T': phoneNumber[x]="8"; break; case 'U': phoneNumber[x]="8"; break; case 'V': phoneNumber[x]="8"; break; case 'W': phoneNumber[x]="9"; break; case 'X': phoneNumber[x]="9"; break; case 'Y': phoneNumber[x]="9"; break; case 'Z': phoneNumber[x]="9"; break; } for (phoneNumber[x],phoneNumber[x].length;phoneNumber++) { printf("answer: %c",phoneNumber[x]); } } }Comment
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Does it compile without errors (if you tried it though)?Comment
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it is error on this line
for (phoneNumber[x];phoneNumber[x].length;phoneNu mber++)
request for member "length" in something not a structure or union...
help pleaseComment
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it is error on this line
for (phoneNumber[x];phoneNumber[x].length;phoneNu mber++)
request for member "length" in something not a structure or union...
when compile error....
help pleaseComment
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You're calling length on the x'th item of the array, not the array itself.Comment
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phonenumber[i] is char, you can't access char using dot as if it was a structure with a member named length. And array has no .length as well. Also, for() loop contains three expressions separated by semicolon - initializer, condition and increment, maybe optional but semicolons are not.Comment
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