Loop won't iterate

[abrown07]

I am trying to create a program and it works perfectly except the program ignores my loop. Here is the piece of the code that this involves:

printf("Please indicate how many generations you wish to calculte: ");
   scanf("%d", &generations);
 
 
 
  for(n=1; n==generations; n++) 
     {
      Population=initial*exp (growth*(1.0-(initial/capacity)));
            
       printf("The population at the next generation will be: %.6f\n", Population);
       
       initial=Population;
     }
      
     
 return(0);
   
}

The problem I'm having is that the program simply ends after the number of desired generations is indicated. Is this because I cannot ask the loop to execute for the number of generations? If so, how would I be able to make that happen?

[jkmyoung]

You want n <= generations.

This is a common mistake. The for loop continues for as long as the rule is true, beginnning with the first iteration. (It's not the ending criteria)

[abrown07]

Thanks,
that was an easy fix!! Im glad haha

also do you know of anyway that the output statment can include a count as well, like say I want to give 50 generations of output right now I have it stating

"The population at the next generation will be : "
50 times all the way down.

is there anyway that I can make the output say:

"The population at generation 2 will be: "
"The population at generation 3 will be: "
and so on

[boltster]

I believe you can just use the n in your print statement

printf("The population at the", n, "generation will be: %.6f\n", Population);

[abrown07]

that is too many arguments for the format i had tried it previously do you know of any other way it could work?

[newb16]

Yes. Start with google, type 'printf', go to the very first link, scroll down to examples section, look at the line
printf ("Decimals: %d %ld\n", 1977, 650000L);
Each format specifier will be replaced with corresponding value in the output.
if you change it to
printf ("Decimals: %d sometextsometex t %ld\n", 1977, 650000L);
it will work too.