how to print a multiple characters?

[arperidot]

i have a really question that's been bugging me for a little too long now. so i want to print this, where 'grade' is a char

 if(average >= 100) { grade = 'A+' ; }
        else if(average >= 90 && average < 100) { grade = 'A' ; }
        else if(average >= 80 && average < 90) { grade = 'B' ; }
        else if(average >= 60 && average < 80) { grade = 'C' ; }
        else if(average >= 50 && average < 60) { grade = 'D'; }
        else if(average < 50) { grade = 'F'; }

everything works except for A+ which prints as +. what seems to be the problem here?

[Adam01]

Your storing 2 characters in one place.
Where as ' ' can only hold one character.

A quick fix would be to define grade as
char grade[2];

Then use grade[0] = 'A' for single grade letters, and then
grade[0] = 'A';
grade[1] = '+';

[Banfa]

But be aware if you store grade as 2 characters

char grade[2];

Then you have exactly that, an array of 2 characters, both of which may or may not hold a value. You do not have a string because a string requires a zero '\0' terminating character and you do not have room in you array for one. To print this you will need to be something interesting using %c twice in a printf statement.

However what you could do instead is declare an array of 3 characters

char grade[3];

and then actually store a string, it might only be a string of 1 or 2 characters but you would then be able to use %s to print it out regardless of the number of characters it contains.

Of course you can't assign with = to a string (in C) so you would have to use strcpy.

[mush1578]

u also write that if(avg>=100){
cout<<"A+"<<end l;
}
it ll be better for u