problem with a function!

[chara3]

I've been developing a programm similar to the stable marriage problem.
I've just started but there is something wrong with the code. The 3rd argument of function saveToFile doesn't work. Can somebody help me?

#include <stdio.h>
#include <io.h>
#include <stdlib.h>
#include <string.h>
//using namespace std;
void saveToFile(char* fileName, int numberOfPersons, char *namesOfPersons)
{
    FILE *myFile;
    if((myFile=fopen(fileName,"w"))==NULL)
    {
        printf("Cannot write file... Using already stored lists.");
        exit(-1);
    }
    else
    {
        for(int i=0;i<numberOfPersons;i++)
        {
                fprintf(myFile, "%s\n",&namesOfPersons[i]);
        }
        fclose(myFile);
    }
}

void dataEntry(char* requestFor)
{
    int numberOfPersons;
        
    printf("How many %ss? ",requestFor);
    scanf("%d",&numberOfPersons);
      
    char *namesOfPersons[numberOfPersons]; //Array of character array(string);
    
    //Ask for Person names    
    for(int i=0;i<numberOfPersons;i++)
    {
      printf("%s name %d: ",requestFor,i);
      scanf("%s",&namesOfPersons[i]);      
    }
       saveToFile(strcat(requestFor,"List.txt"), numberOfPersons, &namesOfPersons);
}
int main(int argc, char *argv[])
{
    dataEntry("Teacher");
    dataEntry("Student");
    dataEntry("Diplwmatikes");
    system("PAUSE");
    return EXIT_SUCCESS;
}

I can't put it in code tags for some reason!

[donbock]

Whenever you pass an array you need to declare the parameter as a pointer to the first element in the array. The first element is a null-terminated string; that is, a char*. Your parameter has to be a pointer to a char* ... or a char**.

Function dataentry defines automatic variable namesOfPersons to hold the array of pointers, but it doesn't allocate any memory to hold the strings pointed to by the array elements. You should review the operation of the "%s" feature of scanf.