mat[i][j] = *(*(mat + i) + j) here mat is a pointer to an array of r elements an

[abhi17]

int mat[r][c];
mat[i][j] = *(*(mat+i) + j) ???

here mat is a pointer to an array of r elements and each elementof mat itself is an array of c elements
then in mat +i ,i gets scaled by c*sizeof(int) thus mat+i is starting address of ith row and then dereferencing it yields first element of ith row but looking at this expression it seems that *(mat + i) is also treated as a address
please help on understanding this way of accessing array elements of multidimensiona l array

[weaknessforcats]

int mat[r][c];
mat[i][j] = *(*(mat+i) + j) ???

*(*(mat+i) + j) is the pointer syntax for mat[i][j]. That is, take the address of mat and add i * c*sizeof(int) to get the address of mat[i]. Then add j * sizeof(int) to get the adress of the element itself, then de-reference that address to get the actual element.

You might read the article Arrays Revealed in the C Insights Forum.

[donbock]

That's Arrays Revealed.