why 'x' is taking always 1.

[amarniit]

#include<stdio. h>
void main ()
{
int x=4,y=78;
if(x=8 && y>65)
printf("x=%d");
else
printf("Bywe");
getch();
}


here i am always geting the value of x is one........... its never change

[Dheeraj Joshi]

if(x=8 && y>65)

x=8 is assignment not condition checking.

It must be :

if(x==8 && y>65)

Regards
Dheeraj Joshi


Note: Please use code tags during posting the code

[Markus]

You don't provide an argument to the printf() function. It should look like: printf("x=%d", x).

[whodgson]

In fact neither of your printf statements are correct.
e.g.
printf("i=%d and x=%f\n",i,x);//Here there are two format specifiers in the format string and two data-field arguements. The number of format specifiers require matching with the data-field arguements.

[amarniit]

ya in printf()it is
printf("x=%d",x );

[sidooh]

you should use printf("x=%d",x );

[Banfa]

Strictly speaking if you wish to see your output immediately it should be

printf("x=%d\n" ,x);

without the newline the system is free to buffer the output until a later time.