how to call an inherited, template class constructor from initializerlist of an inheriting, non-template class constructor

[l.s.rockfan@web.de]

Hello,

how do i have to call an inherited, templated class constructor from the
initializer list of the inheriting, non-templated class constructor?

example code:


template<typena me T>
class A
{
protected:
sometype* something;
T something_else; /*gives the template some sense here*/
public:
A(sometype* param) : something(param ) {};
}


class B : public A<int>
{
public:
B(sometype* param) : A(param) {}; // <== Compiler Error

/* further member functions */
}


The compiler always tries to identify A as a member variable not being
found, instead of the base class' constructor.

[Obnoxious User]

Re: how to call an inherited, template class constructor frominitializer list of an inheriting, non-template class constructor

On Fri, 14 Nov 2008 21:28:53 +0100, l.s.rockfan@web .de wrote:

Hello,
>
how do i have to call an inherited, templated class constructor from the
initializer list of the inheriting, non-templated class constructor?
>
example code:
>
>
template<typena me T>
class A
{
protected:
sometype* something;
T something_else; /*gives the template some sense here*/
public:
A(sometype* param) : something(param ) {};
}
>
>
class B : public A<int>
{
public:
B(sometype* param) : A(param) {}; // <== Compiler Error
>

B(sometype * param) : A<int>(param) {}

--
OU
Remember 18th of June 2008, Democracy died that afternoon.

http://frapedia.se/wiki/Information_in_English

[l.s.rockfan@web.de]

Re: how to call an inherited, template class constructor from initializerlist of an inheriting, non-template class constructor

Obnoxious User wrote:

On Fri, 14 Nov 2008 21:28:53 +0100, l.s.rockfan@web .de wrote:
>

>Hello,
>>
>how do i have to call an inherited, templated class constructor from the
>initializer list of the inheriting, non-templated class constructor?
>>
>example code:
>>
>>
>template<typen ame T>
>class A
>{
>protected:
> sometype* something;
> T something_else; /*gives the template some sense here*/
>public:
> A(sometype* param) : something(param ) {};
>}
>>
>>
>class B : public A<int>
>{
>public:
> B(sometype* param) : A(param) {}; // <== Compiler Error
>>

>
B(sometype * param) : A<int>(param) {}
>

Thanks.

Mysterious, it really works.

All the time I tried it before, I coded it outside the class body like

B::B(sometype* param) : A<int>(param) {}

and it didn't work because of an ld error.


When I move it inside the class body (like in my example code above) it
works.

Could someone explain this behaviour to me, please?

[l.s.rockfan@web.de]

Re: how to call an inherited, template class constructor from initializerlist of an inheriting, non-template class constructor

Obnoxious User wrote:

On Fri, 14 Nov 2008 21:28:53 +0100, l.s.rockfan@web .de wrote:
>

>Hello,
>>
>how do i have to call an inherited, templated class constructor from the
>initializer list of the inheriting, non-templated class constructor?
>>
>example code:
>>
>>
>template<typen ame T>
>class A
>{
>protected:
> sometype* something;
> T something_else; /*gives the template some sense here*/
>public:
> A(sometype* param) : something(param ) {};
>}
>>
>>
>class B : public A<int>
>{
>public:
> B(sometype* param) : A(param) {}; // <== Compiler Error
>>

>
B(sometype * param) : A<int>(param) {}
>

Thanks.

Mysterious, it really works.

All the time I tried it before, I coded it outside the class body like

B::B(sometype* param) : A<int>(param) {}

and it didn't work because of an ld error: undefined reference to
A<int>::A(param ).

But when I move it inside the class body (like in my example code above)
it works.

Could someone explain this behaviour to me, please?