Re: How to retrieve data from array of pointers or from a struct?

[Pawel Dziepak]

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Victor wrote:
<snip>

unsigned long long seed = *(dataPatternPt r + 2); // This one
works during compile
unsigned long long seed = *(dataPatternPt r + i); // *********
ERROR ****** But why does this one not work?

You are using an array of pointers not an array of long long values.
Don't forget that sizeof(long long) != sizeof(long long*). See below for
more description.

/projects/svdc/aurora.validati on/work/vhnguyen/aurora_validati on/uboot/
examples/zzzmain.c:295: undefined reference to `memcpy'
make[1]: *** [zzzmain] Error 1
>
>
Does anyone know why? It seems memcpy is not found in #include files
but what library memcpy should reside in?

It looks like you are not linking your output binaries with the standard
C library in which memcpy is placed, are you? You for sure changed
default stettings of your compiler/linker thus it's off topic for clc.

struct key {
unsigned long long *pattern;
} dataPattern[] = {
0x0000000000000 000LL,
0xFFFFFFFFFFFFF FFFLL,
0x5555555555555 555LL,
0xAAAAAAAAAAAAA AAALL,
0xCCCCCCCCCCCCC CCCLL,
0x3333333333333 333LL,
0xEEEEEEEEEEEEE EEELL,
0x7777777777777 777LL,
0x0000000000000 001LL,
0xFFFFFFFFFFFFF FFELL,
0xABCDEF0123456 789LL
};
>
Actually I also have another 3rd question indicated below:
>
int sizeOfStruct = sizeof(struct key); // Here size is 4 bytes
int totalSize = sizeof(dataPatt ern); //Here sizeof returns
number bytes (44) . Question: Should it return 88 bytes (11 patterns
* 8 bytes each) instead of 44 ?

Structure key consist of a *pointer* to long long. Despite the fact long
long appears to be 8 bytes on your architecture, you have 4 byte long
pointers. You should use "unsigned long long pattern;" (not a pointer).

Pawel Dziepak
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