How to use *input[] as argument

[kjells_@hotmail.com]

How can I call a function which takes an argument like this

void func(char *inout[]);

This works okay:
char *pOutPut[500];
for(int i = 0; i < 10; i++)
{
pOutPut[i] = (char*) malloc(33);
}
func(pOutPut);

But if I don't want to use dynamic memory
char pout[10][33];
func(pout); // Compiler error !

func(char **)pout); // exception!

[Flash Gordon]

Re: How to use *input[] as argument

kjells_@hotmail .com wrote, On 28/09/08 19:54:

How can I call a function which takes an argument like this
>
void func(char *inout[]);

<snip>

But if I don't want to use dynamic memory
char pout[10][33];
func(pout); // Compiler error !

<snip>

Start off with question 6.18 of the comp.lang.c FAQ at http://c-faq.com/
then look through the rest of section 6.
--
Flash Gordon
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