How to make the vector size unchanged but values not?

[shuisheng]

Dear All,

I have a question. Assume

#include <vector>
using namespace std;

class A
{
private:
vector<intv;
int n;

public:
void Reset(int i)
{
n = i;
v.resize(i);
}

vector<int>& Vector()
{
return v;
}
};

For class A, 'n' and the size of 'v' must be always consistent. Every
time n is changed, v is reset with the size n. If n is not changed,
the vector v's size can not change, but its values can change, such as

A::Vector()[2] = 3;

But user can use A::Vector().res ize() to change the size of the
vector. How can I avoid it and still keep all the std::vector 's
functions to change the values?

Thanks and best regards,

Shuisheng

[Kai-Uwe Bux]

Re: How to make the vector size unchanged but values not?

shuisheng wrote:

Dear All,
>
I have a question. Assume
>
#include <vector>
using namespace std;
>
class A
{
private:
vector<intv;
int n;
>
public:
void Reset(int i)
{
n = i;
v.resize(i);
}
>
vector<int>& Vector()
{
return v;
}
};
>
For class A, 'n' and the size of 'v' must be always consistent. Every
time n is changed, v is reset with the size n. If n is not changed,
the vector v's size can not change, but its values can change, such as
>
A::Vector()[2] = 3;
>
But user can use A::Vector().res ize() to change the size of the
vector. How can I avoid it and still keep all the std::vector 's
functions to change the values?

The easy way is to ditch the variable i. Since it cannot be observed from
the outside, it does not make any sense to carry it around. Probably this
possibility is due to oversimplificat ion of the problem and does not arise
in the original setting.

The standard way would be to not expose the internal vector by means of a
Vector() method but to narrow down its interface and make the needed
functions available through forwarding. They would also update i.

The hard way would be to not return a reference in the Vector() method, but
a smart reference that updates i upon destruction. Since we cannot overload
the dot-operator, there are some limitations to this method. We can,
however, return a smart pointer.


All in all, you seem to have a design problem that is best solved by
avoiding the problem. What is the underlying conundrum that you are
struggling with?


Best

Kai-Uwe Bux

[shuisheng]

Re: How to make the vector size unchanged but values not?

On Sep 19, 10:34 am, Kai-Uwe Bux <jkherci...@gmx .netwrote:

shuisheng wrote:

Dear All,

>

I have a question. Assume

>

#include <vector>
using namespace std;

>

class A
{
private:
  vector<intv;
  int n;

>

public:
  void Reset(int i)
  {
    n = i;
    v.resize(i);
  }

>

  vector<int>& Vector()
  {
    return v;
  }
};

>

For class A, 'n' and the size of 'v' must be always consistent. Every
time n is changed, v is reset with the size n. If n is not changed,
the vector v's size can not change, but its values can change, such as

>

A::Vector()[2] = 3;

>

But user can use A::Vector().res ize() to change the size of the
vector. How can I avoid it and still keep all the std::vector 's
functions to change the values?

>
The easy way is to ditch the variable i. Since it cannot be observed from
the outside, it does not make any sense to carry it around.  Probably this
possibility is due to oversimplificat ion of the problem and does not arise
in the original setting.
>
The standard way would be to not expose the internal vector by means of a
Vector() method but to narrow down its interface and make the needed
functions available through forwarding. They would also update i.
>
The hard way would be to not return a reference in the Vector() method, but
a smart reference that updates i upon destruction. Since we cannot overload
the dot-operator, there are some limitations to this method. We can,
however, return a smart pointer.
>
All in all, you seem to have a design problem that is best solved by
avoiding the problem. What is the underlying conundrum that you are
struggling with?
>
Best
>
Kai-Uwe Bux

The underlying problem is like that: I have a 2-D (two dimensional)
field (or array), the field points are arranged regularly along x and
y axis, which looks like a grid as follows,

y2 . . . .
y1 . . . .
y0 . . . .
x0 x1 x2 x3

where the dots denote field points. Given two vectors: xv and yv, the
grid points will be well defined. And the 2-D field have a size of
(size of xv) by (size of yv). So every time reset xv and yv, the size
of 2-D field will changed. But if the xv and yv do not change, only
the field values can change. For 2-D filed/array, I use blitz::array,
which is similar to std::vector but is 2-D.

Thank you for your help!

[Kai-Uwe Bux]

Re: How to make the vector size unchanged but values not?

shuisheng wrote:

On Sep 19, 10:34 am, Kai-Uwe Bux <jkherci...@gmx .netwrote:

>shuisheng wrote:

Dear All,

>>

I have a question. Assume

>>

#include <vector>
using namespace std;

>>

class A
{
private:
vector<intv;
int n;

>>

public:
void Reset(int i)
{
n = i;
v.resize(i);
}

>>

vector<int>& Vector()
{
return v;
}
};

>>

For class A, 'n' and the size of 'v' must be always consistent. Every
time n is changed, v is reset with the size n. If n is not changed,
the vector v's size can not change, but its values can change, such as

>>

A::Vector()[2] = 3;

>>

But user can use A::Vector().res ize() to change the size of the
vector. How can I avoid it and still keep all the std::vector 's
functions to change the values?

>>
>The easy way is to ditch the variable i. Since it cannot be observed from
>the outside, it does not make any sense to carry it around.  Probably
>this possibility is due to oversimplificat ion of the problem and does not
>arise in the original setting.
>>
>The standard way would be to not expose the internal vector by means of a
>Vector() method but to narrow down its interface and make the needed
>functions available through forwarding. They would also update i.
>>
>The hard way would be to not return a reference in the Vector() method,
>but a smart reference that updates i upon destruction. Since we cannot
>overload the dot-operator, there are some limitations to this method. We
>can, however, return a smart pointer.
>>
>All in all, you seem to have a design problem that is best solved by
>avoiding the problem. What is the underlying conundrum that you are
>struggling with?
>>
>Best
>>
>Kai-Uwe Bux

>
The underlying problem is like that: I have a 2-D (two dimensional)
field (or array), the field points are arranged regularly along x and
y axis, which looks like a grid as follows,
>
y2 . . . .
y1 . . . .
y0 . . . .
x0 x1 x2 x3
>
where the dots denote field points. Given two vectors: xv and yv, the
grid points will be well defined. And the 2-D field have a size of
(size of xv) by (size of yv). So every time reset xv and yv, the size
of 2-D field will changed. But if the xv and yv do not change, only
the field values can change. For 2-D filed/array, I use blitz::array,
which is similar to std::vector but is 2-D.

Hm, the least invasive I can think of, is to split the setter/getter
function in two:

vector< int const & get_x ( void ) const {
return xy;
}

void set_x ( vector< int const & val ) {
xy = val;
// do whatever is needed to update the 2d-array
}

// similarly for y.

However, getter and setter methods still smell NotSoGood(tm). The preferred
way of going about this is to make the vectors and the 2d-array strictly
private members of the class and to devise an interface that describes how
an object of that type responds to messages. That way, proper encapsulation
is ensured. That, however, will require a good deal of knowledge about the
application domain where this class will be used.


Best

Kai-Uwe Bux

[maverik]

Re: How to make the vector size unchanged but values not?

On Sep 19, 6:55 pm, shuisheng <shuishen...@ya hoo.comwrote:

On Sep 19, 10:34 am, Kai-Uwe Bux <jkherci...@gmx .netwrote:

[...]

For 2-D filed/array, I use blitz::array,

which is similar to std::vector but is 2-D.

You can use splices for emulating 2D arrays.