Error message explained

[esclepius@gmail.com]

In the following little bit of code, I understand what and why the
error is, ( lack of parentheses in *pp.y , thus declaring 'y' a
pointer, which it is not) but what I don't get is the error the
compiler raises.

int main (int argc, const char * argv[]) {

struct point {
int x;
int y;
};
struct point origin;
struct point *pp;

pp= &origin;

origin = makepoint(23, 67);

printf("%d, %d\n", (*pp).x, *pp.y); /*error: request for member 'y'
in something not a structure or union */

}


I am sure I will get this again at some point, so any logic here is
appreciated, or perhaps I am looking too deeply.

Thanks.

[Bartc]

Re: Error message explained

<esclepius@gmai l.comwrote in message
news:cda404cf-28c7-4fd5-ac28-1c26ddd5de7f@l3 3g2000pri.googl egroups.com...

In the following little bit of code, I understand what and why the
error is, ( lack of parentheses in *pp.y , thus declaring 'y' a
pointer, which it is not) but what I don't get is the error the
compiler raises.
>
int main (int argc, const char * argv[]) {
>
struct point {
int x;
int y;
};
struct point origin;
struct point *pp;
>
pp= &origin;
>
origin = makepoint(23, 67);
>
printf("%d, %d\n", (*pp).x, *pp.y); /*error: request for member 'y'
in something not a structure or union */
>
}

Since the parentheses seem to fix things, without them the term is
presumably parsed as:

*(pp.y)

which won't work because pp is a pointer, not a struct as expected. (*pp).y
works but best to use pp->y

--
Bartc

[mdh]

Re: Error message explained

On Aug 23, 9:01 am, "Bartc" <b...@freeuk.co mwrote:

>
which won't work because pp is a pointer, not a struct as expected. (*pp)..y
works but best to use pp->y
>

Thank you for that...just getting to the "->" operator.