Question about the order of incrementing i

[dissectcode]

Hello - I have this code, and I want to make sure it is incrementing like I am hoping...can someone look at the logic and verify whats happening?

int p[50];
i = 0;

p[i++] = 'P';
p[i++] = 20;
p[i++] = 3;
p[i]  =  checksumFunct(p[1] , (i - 1) );
i++;

so, I want to set the array elements, p[0] = P, p[1] = 20, p[3] = 3, and p[4]=checksum value, and then i is 5. Is this what is happening? Is the 4th element actually p[3]?? Please help...

btw - I obviously can't increment i and use it in the checksum funciton (illegal b/c sequence points)...
thanks!

[Banfa]

I want to set the array elements, p[0] = P, p[1] = 20, p[3] = 3, and p[4]=checksum value, and then i is 5.

Do you realise that in this list you have left out p[2], your indexes go 0, 1, 3, 4?

If you want want you have written then no because you have missed an increment of i and it's final value is 4. If on the other hand you meant to write

p[0] = P, p[1] = 20, p[2] = 3, and p[3]=checksum value, and then i is 4

then the code you have is exactly right.

[dissectcode]

Oops you are right - and thank you for the clairity!

[sicarie]

Oops you are right - and thank you for the clairity!

Another debugging tip that I have found useful over the years is to use print statements to figure out everything that is going on.

So in your test, you can print out i after each statement to figure out the value of i before and after those statements (as well as any other variables you might be interested in).

I usually make a 'debug_printVar s()' function so I only have to code it once, and then just call that function each time I want to see what is going on.