How can I transform source range to destination range that is thesame as source?

[Lambda]

I'd like to change all the character in a array to lower case.
I find transform() is convenient.

Because the array is large, I don't want to define another array. I
tried:

transform(buffe r, buffer + size, buffer, tolower);

From the output, I find it works.
But when I compile it with Visual C++,
I find a warning that says 'Function call with parameters that may be
unsafe'.

I shouldn't use transform that way?
I must define another array to store the result or
do it without transform?

[Sam]

Re: How can I transform source range to destination range that isthe same as source?

Lambda writes:

I'd like to change all the character in a array to lower case.
I find transform() is convenient.
>
Because the array is large, I don't want to define another array. I
tried:
>
transform(buffe r, buffer + size, buffer, tolower);
>
From the output, I find it works.
But when I compile it with Visual C++,
I find a warning that says 'Function call with parameters that may be
unsafe'.
>
I shouldn't use transform that way?

I see nothing wrong with this. The only thing that's wrong here is your
choice of using Microsoft's technology for learning C++. It's a known cause
of brain rot.

I must define another array to store the result or
do it without transform?

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[James Kanze]

Re: How can I transform source range to destination range that is thesame as source?

On Jul 16, 12:43 pm, Lambda <stephenh...@gm ail.comwrote:

I'd like to change all the character in a array to lower case.
I find transform() is convenient.

Because the array is large, I don't want to define another array. I
tried:

transform(buffe r, buffer + size, buffer, tolower);

From the output, I find it works.

Depending on the includes, it's likely to not even compile. And
if it does, the results have undefined behavior.

But when I compile it with Visual C++,
I find a warning that says 'Function call with parameters that
may be unsafe'.

Which one?

I shouldn't use transform that way?

No.

I must define another array to store the result or
do it without transform?

No, but you do have to provide a functional object that is
unambiguous and that works correctly on the data type. You also
should be using std::vector instead of whatever; it would make
life a lot easier.

And finally, of course, you should be aware that upper to lower
case is not necessarily a one to one mapping, and that it is
very locale dependent.

--
James Kanze (GABI Software) email:james.kan ze@gmail.com
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