system call as variabe

[rudra]

i have written a code::
#include <stdio.h>
#include <stdlib.h>
int main()
{
int sys;
int i686;
sys=system("/bin/uname -m");
//printf ("%d",sys);
if (sys==i686){
printf("the syst. 32 bit");
}
else
printf("64but") ;
}
where i want the output of "system("/bin/uname -m")" as the variable
sys.....to find the machine structure.this procedure is not quite
working. can you people suggest me some way?

[Ian Collins]

Re: system call as variabe

rudra wrote:

i have written a code::
#include <stdio.h>
#include <stdlib.h>
int main()
{
int sys;
int i686;
sys=system("/bin/uname -m");
//printf ("%d",sys);
if (sys==i686){
printf("the syst. 32 bit");
}
else
printf("64but") ;
}
where i want the output of "system("/bin/uname -m")" as the variable
sys.....to find the machine structure.this procedure is not quite
working. can you people suggest me some way?

Lack of whitespace in the code?

The serious answer is system() does not return the value printed by the
command you pass to it.

Check your man pages, then ask about popen() on comp.unix.progr ammer.

--
Ian Collins.

[viza]

Re: system call as variabe

On Tue, 08 Jul 2008 22:21:39 -0700, rudra wrote:

sys=system("/bin/uname -m");

Systems which provide a uname program will probably provide a uname
system call or library function. Lookup:

man 2 uname (on Linux)
man 3 uname (on BSD)

(just "man uname" will get you the manual page for the uname(1), which is
the application)