Question about struct in shared memory (C on linux)

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  • hugo.arregui@gmail.com

    Question about struct in shared memory (C on linux)

    Hi!

    I have two struts like that:

    struct {
    int num;
    int num2;
    struct b arrayOfB[SIZE];
    } a;

    struct {
    int num3;
    int num4
    } b;

    I put struct a into Shared Memory:
    shmid = shmget(IPC_PRIV ATE, sizeof(struct b), 0666)

    and atach it in two process:
    ptr = shmat(shmid, 0, 0);

    This works fine, but now i must delete the constant SIZE:

    I will obtain the SIZE in runtime, before execute the shmget function.

    the new struct a:

    struct {
    int num;
    int num2;
    struct b *arrayOfB;
    } a;

    now:

    I put struct a into Shared Memory:
    shmid = shmget(IPC_PRIV ATE, sizeof(struct a) + sizeof(struct b) *
    size, 0666);

    and atach it in two process:
    ptr = shmat(shmid, 0, 0);

    my question is: how can tell arrayOfB to point over the shared memory?

    i thought:

    struct a *ptr,p2*;
    p2 = ptr; //ptr is the shmat return
    p2++;
    ptr->arrayOfB

    but doesn't work. in another way i read about the shmat parametrs, but
    don't understand how (if its possible) use to solve my trouble.

    Thanks.
  • David Resnick

    #2
    Re: Question about struct in shared memory (C on linux)

    On Jul 3, 12:29 pm, "hugo.arre...@g mail.com" <hugo.arre...@g mail.com>
    wrote:
    Hi!
    >
    I have two struts like that:
    >
    struct {
    int num;
    int num2;
    struct b arrayOfB[SIZE];
    >
    } a;
    >
    struct {
    int num3;
    int num4
    >
    } b;
    >
    I put struct a into Shared Memory:
    shmid = shmget(IPC_PRIV ATE, sizeof(struct b), 0666)
    >
    and atach it in two process:
    ptr = shmat(shmid, 0, 0);
    >
    This works fine, but now i must delete the constant SIZE:
    >
    I will obtain the SIZE in runtime, before execute the shmget function.
    >
    the new struct a:
    >
    struct {
    int num;
    int num2;
    struct b *arrayOfB;
    >
    } a;
    >
    now:
    >
    I put struct a into Shared Memory:
    shmid = shmget(IPC_PRIV ATE, sizeof(struct a) + sizeof(struct b) *
    size, 0666);
    >
    and atach it in two process:
    ptr = shmat(shmid, 0, 0);
    >
    my question is: how can tell arrayOfB to point over the shared memory?
    >
    i thought:
    >
    struct a *ptr,p2*;
    p2 = ptr; //ptr is the shmat return
    p2++;
    ptr->arrayOfB
    >
    but doesn't work. in another way i read about the shmat parametrs, but
    don't understand how (if its possible) use to solve my trouble.
    >
    Thanks.
    Forgetting the details of shared memory (which you would get better
    advice in comp.unix.progr ammer, btw, as it is not standard C), you
    could consider using the struct hack to solve your problem. See, e.g.


    -David

    Comment

    • hugo.arregui@gmail.com

      #3
      Re: Question about struct in shared memory (C on linux)

      Forgetting the details of shared memory (which you would get better
      advice in comp.unix.progr ammer, btw, as it is not standard C), you
      could consider using the struct hack to solve your problem. See, e.g.http://c-faq.com/struct/structhack.html
      >
      -David
      Thanks you David, but my problem is how to do that in shared memory, i
      will try in comp.unix.progr ammer.

      Thanks again.

      Comment

      • David Resnick

        #4
        Re: Question about struct in shared memory (C on linux)

        On Jul 3, 2:52 pm, "hugo.arre...@g mail.com" <hugo.arre...@g mail.com>
        wrote:
        Forgetting the details of shared memory (which you would get better
        advice in comp.unix.progr ammer, btw, as it is not standard C), you
        could consider using the struct hack to solve your problem.  See, e.g..http://c-faq.com/struct/structhack.html
        >
        -David
        >
        Thanks you David, but my problem is how to do that in shared memory, i
        will try in comp.unix.progr ammer.
        >
        Thanks again.
        The first option in the faq site should work as well with shared
        memory as elsewhere as far as I know. i.e. put in your structure
        this:

        struct b arrayOfB[1];

        But allocate enough space for the structure AND the desired number of
        "b" elements, then use it. This avoids the problem of having a
        pointer to another block of memory in the struct...

        -David

        Comment

        • David Thompson

          #5
          Re: Question about struct in shared memory (C on linux)

          On Thu, 3 Jul 2008 09:29:37 -0700 (PDT), "hugo.arregui@g mail.com"
          <hugo.arregui@g mail.comwrote:
          struct {
          int num;
          int num2;
          struct b arrayOfB[SIZE];
          } a;
          >
          struct {
          int num3;
          int num4
          } b;
          <snip shared-memory>
          Aside: you used sizeof(struct b) where you needed (struct a).

          The shared-memory part is offtopic as it is not standard in C; but
          issues of laying-out and accessing data in arbitrary memory, whether
          it happened to come from shm* or say malloc (a_zillion), is ontopic.
          At least if the memory is suitably aligned in the first place, and
          both <offtopicshma t and <ontopicmallo c are (for all types).
          [now] I will obtain the SIZE in runtime, before ... shmget ...
          struct {
          int num;
          int num2;
          struct b *arrayOfB;
          } a;
          <snip>
          my question is: how can tell arrayOfB to point over the shared memory?
          >
          As already answered, you don't need this change; you can use the
          'struct hack' in C89, or the equivalent but standard 'flexible array
          member' in C99, to get the same 'in-place' layout as above.

          But if you WANT to change to a pointer:
          struct a *ptr,p2*;
          Syntax error; should be *ptr, *p2;
          p2 = ptr; //ptr is the shmat return
          p2++;
          ptr->arrayOfB
          >
          You're close. With the corrected declaration above, this gives you p2
          pointing just after the struct-a. IF that location is suitably aligned
          for a struct-b, you can just do ptr->arrayOfB = (struct b*) p2;
          In fact you don't need a separate variable, just
          ptr->arrayOfB = (struct b*) (ptr+1);
          /* or equivalently */ = (struct b*) &ptr[1];

          Unfortunately there is no standard way to determine what alignment is
          needed for a struct-b, or provided by a struct-a (the size of any type
          in C must be a multiple of its required alignment, to make arrays
          work), so this can be unsafe. For the particular structs you showed,
          it is extremely likely that any requirement for struct-a will (also)
          satisfy struct-b, but it isn't absolutely 100% portably guaranteed.

          If you want to use a pointer and handle the possible alignment issue,
          simplest to use a union which is guaranteed to align for either:

          struct a * aptr = shmat (...);
          union x { struct a a; struct b b; } * xptr = (union x *) aptr;
          aptr->arrayOfB = (struct b*) (xptr + 1);
          /* this is guaranteed located after the struct-a,
          AND aligned for a struct-b. It may _possibly_ be
          offset more than actually needed and waste some space,
          but on most modern systems this isn't worth worrying about,
          unless your (individual) structures are truly huge,
          in which case post a more specific example
          and we can get into the more arcane methods. */

          - formerly david.thompson1 || achar(64) || worldnet.att.ne t

          Comment

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