parsing error

[Medvedev]

when i try to read the first byte from an EXE file it's give different
results
code:
FILE *me,*u;
char buf_me[1];
char buf_u[1];

me= fopen(argv[0],"rb");
u= fopen(argv[1],"rb+");

fread(buf_me,si zeof(char),1,me );
fread(buf_u,siz eof(char),1,u);

printf("%s\n",b uf_me);
printf("%s\n",b uf_u);

----
when you run this code and put EXE file as an argument , the program
will print
M
MM

why it double the byte in the second time

[Ian Collins]

Re: parsing error

Medvedev wrote:

when i try to read the first byte from an EXE file it's give different
results
code:
FILE *me,*u;
char buf_me[1];
char buf_u[1];
>
me= fopen(argv[0],"rb");
u= fopen(argv[1],"rb+");
>
fread(buf_me,si zeof(char),1,me );

sizeof(char) is one by definition.

fread(buf_u,siz eof(char),1,u);
>
printf("%s\n",b uf_me);
printf("%s\n",b uf_u);
>

These to lines invoke undefined behaviour, buf_me and buf_u are not null
terminated C style strings.

c.l.c is a better place for pure C questions.

--
Ian Collins.