Convert two char into one int

[Mariano]

I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

[Kenny McCormack]

Re: Convert two char into one int

In article <8a82a41a-1992-4fa3-9c9b-bc4f6c2b3d6b@e3 9g2000hsf.googl egroups.com>,
Mariano <mariano.caland ra@gmail.comwro te:

>I have this lines:
>
>char *chr;
>int integ;
>num[0] = '1';
>num[1] = '9';
>
>How I could obtain value 19 in the integ variable????
>Hi to all.

Continue with:

num[2] = 0;
sscanf(num,"%d" ,&integ):

[Eric Sosman]

Re: Convert two char into one int

Mariano wrote:

I have this lines:
>
char *chr;
int integ;
num[0] = '1';
num[1] = '9';
>
How I could obtain value 19 in the integ variable????

Assuming `num' is an array of characters (two or more),

integ = (num[0] - '0') * 10 + (num[1] - '0');

will do it.

--
Eric.Sosman@sun .com

[Fred Yu]

Re: Convert two char into one int


"Mariano" <mariano.caland ra@gmail.com>
:8a82a41a-1992-4fa3-9c9b-bc4f6c2b3d6b@e3 9g2000hsf.googl egroups.com...

>I have this lines:
>
char *chr;
int integ;
num[0] = '1';
num[1] = '9';
>
How I could obtain value 19 in the integ variable????
Hi to all.
>

integ = atoi(num[0])*10+atoi(num[1]);

[pete]

Re: Convert two char into one int

Fred Yu wrote:

"Mariano" <mariano.caland ra@gmail.com>
:8a82a41a-1992-4fa3-9c9b-bc4f6c2b3d6b@e3 9g2000hsf.googl egroups.com...

>I have this lines:
>>
>char *chr;
>int integ;
>num[0] = '1';
>num[1] = '9';
>>
>How I could obtain value 19 in the integ variable????
>Hi to all.
>>

>
integ = atoi(num[0])*10+atoi(num[1]);

That's wrong.
num[0] is not a pointer to a string.
atoi takes a pointer to a string as an argument.

int atoi(const char *nptr);

--
pete

[Nick Keighley]

Re: Convert two char into one int

On 26 Jun, 02:15, pete <pfil...@mindsp ring.comwrote:

Fred Yu wrote:

"Mariano" <mariano.calan. ..@gmail.com>
:8a82a41a-1992-4fa3-9c9b-bc4f6c2b3...@e3 9g2000hsf.googl egroups.com...

I have this lines:

>

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

>

How I could obtain value 19 in the integ variable????
Hi to all.

>

integ = atoi(num[0])*10+atoi(num[1]);

>
That's wrong.
num[0] is not a pointer to a string.

and num may not be a valid string, we don't
know if there's a terminating nul character

atoi takes a pointer to a string as an argument.

and has poor error handling

int atoi(const char *nptr);

--
Nick Keighley