In which line it displays error?

[sasimca007]

1. #define CIRCUM(R) (3.14*R*R);
2. main()
3. {
4. float r=1.0,c;
5. c= CIRCUM(r);
6. printf("n%f",c) ;
7. if(CIRCUM(r))== 6.28)
8. printf("nGobble dygook");
9. }

[arnaudk]

Read the posting guidlines before posting on this forum: Posting Homework or Coursework Questions and Answers.

[r035198x]

In which line it displays error?

Where do you think it displays the error?

[Laharl]

If you're not sure where the error's going to be, try to compile it and the compiler will tell you where the error is. Or where it thinks the error is, which isn't always quite the same thing, especially when curly brace errors are involved.

[JosAH]

btw, that macro sucks and not because pi doesn't equal 3.14.

kind regards,

Jos

[Sick0Fant]

btw, that macro sucks and not because pi doesn't equal 3.14.

kind regards,

Jos

Is it because it computes the area instead of circumference, or is it the mere fact that he's using a macro for something like this? :-)

[JosAH]

Is it because it computes the area instead of circumference, or is it the mere fact that he's using a macro for something like this? :-)

Nope, have a look at that macro definition again:

[code=c]
#define CIRCUM(R) (3.14*R*R);
[/code]

that semicolon at the end is a big nono, i.e. that macro can not be used as an
expression, e.g. CIRCUM(r)+1 but that's not the most important blooper: try to
evaluate it for the radius 'a+b', i.e. CIRCUM(a+b). That's why that macro sucks.

kind regards,

Jos

[dtimes6]

You should never compare the float or double directly.