C++ function that will convert a 24bit color pixel

[SpecialKay]

Hey guys,

so i was given this question by one of my dads friends. With no information or turtorial. Just a paper and a pencil. Needless to say, it did not go well, and now my brain want to know the answer. I will try and remember the question as best i can.

Write a C++ function that will convert a 24bit color pixel in the follow format

RGB24(8:8:8)

into a 16bit color pixel

RGB16(5:6:5)

ensure that all the proper variable checking is done.

i have never worked on anything like this, so i would love any feed back.

Thanks!

[weaknessforcats]

The 24-bit R is 8 bits and that can hold a value 0-255.
The 16-bit R is 5 bits and that can hold a value 0-31.

You might think about (24-bit R) % 31 to get the 16-bit R.

[SpecialKay]

what does it mean, when you have

RGB24(8:8:8)

i mean, i can assume that this means 8red 8 green 8 blue.

but how would i grab the value of red? from RGB

RGB24[0] = RGB16[0]%31?

[Savage]

what does it mean, when you have

RGB24(8:8:8)

i mean, i can assume that this means 8red 8 green 8 blue.

but how would i grab the value of red? from RGB

RGB24[0] = RGB16[0]%31?

Simple.

24bit pixel is represented with 32 bit integer.

in this format 0x00RRGGBB (00 becomes AA if you are using RGBA format),so which logical operator are you going to use to extract only parts of it?

[SpecialKay]

What is an RGBA format? and i would assume one would us the Modulas operatior to extract parts of it. This seems like its just a Slightly more complicated version on a "Change Calculator"

[oler1s]

What is an RGBA format?

Is it really that hard to Google?

i would assume one would us the Modulas operatior to extract parts of it

Modulus? Whoa, hold on there. This isn't a decimal number. It's in hexadecimal. The assumption here is that you understand the basic relationship between hexadecimal numbers and binary numbers. And that you are aware of bitwise operations. To be specific, you should understand NOT, AND, OR, XOR, and the left/right shifts. If you know these three things, you should know how to work with RGBA numbers.

[SpecialKay]

Your a meanie :P

Wowie thats a lot of information. The orignal problem did not mention anything about fadeing. So that means i would be dealing with just a normal RGB?

I understand all of the Shitfs and Or,And,XOR. I have never used them in a program. But i understand the concept.

Im still not sure how to work with all of this...

and, if an int is 32bits, and we are workin with 24bitRGB pixel. where do the other bits go... i understand it with the RGBA, the remaining bits are used for transparicy (If i read right).

EDIT:
by basic relationship between HEX and DEC you mean what? how to convert them?

[weaknessforcats]

[code=c]
typedef struct RGB
{
unisgned char blue;
unsigned char green;
unsigned char red;
} RGB;
[/code]

RGB is just a struct with three 8-bit members.

All you have to do is convert these members to the other struct.

You should not need to work at the bit level.

[oler1s]

So that means i would be dealing with just a normal RGB?

Yes.

and, if an int is 32bits, and we are workin with 24bitRGB pixel. where do the other bits go...

Nowhere. You have 32 bits, but you only use 24. Yes, they get wasted.

by basic relationship between HEX and DEC you mean what? how to convert them?

No, I'm talking about relationship between hexadecimal and binary. Right, because you have a number of binary operations. But you work with binary numbers in hexademical instead. If you're confused, let me give you an example.

I have 1111 1110. What bit operation could i do to get 1111?
Then, I have FE. What bit operation could I do to get F?

It isn't complicated, but you need to realize the relationship between hex and bin.

EDIT: If you are given a struct of the component colors individually, that's not really RGB conversion, then. The idea is that you have a packed value that you need to extract the RGB components with bitwise operations and pack into another format.

[SpecialKay]

I have 1111 1110. What bit operation could i do to get 1111?
Then, I have FE. What bit operation could I do to get F?

1111 1110
0000 1110 xor

=
1111

maybe?

and since FE = 1111 1110 it would be the same operation?

[SpecialKay]

[code=c]
typedef struct RGB
{
unisgned char blue;
unsigned char green;
unsigned char red;
} RGB;
[/code]

why are you using char?

EDIT:
im also not seeing the big picture really. How do i convert a 24bits, to 16bits?

[Savage]

1111 1110
0000 1110 xor

=
1111

maybe?

and since FE = 1111 1110 it would be the same operation?

But why set the whole mask,in this case you need to know bits of the rest instead of only knowing bits you need.

What if you had 1011 1110 and you only needed to extract the two highest bits?

You would need to use mask like:0011 1110,instead of having a chance to easily put this mask:

1100 0000 with binary AND operator.

Converting the example to HEX say you have 0x00FFAABB and you want to pull out FF and shift it so it comes down to [0-255] interval.How would you do that with XOR?

[SpecialKay]

would you have to convert it to 111111111010101 010111011.

or is there a way to xor the hex value

EDIT:

111111111010101 010111011
111111111101010 101000100 xor =

010101010111011

not too sure about the shift part.
This is way more complicated then i thought

[Savage]

would you have to convert it to 111111111010101 010111011.

or is there a way to xor the hex value

EDIT:

111111111010101 010111011
111111111101010 101000100 xor =

010101010111011

not too sure about the shift part.
This is way more complicated then i thought

There is a way to do bitwise operations under hex.You just write it in hex notation.

For example:

0x00FF99CC,if I were going to extract 99 from here I would use:

0x00FF99CC &0x0000FF00=0x0 0009900,shift it 8 places to the right >>

0x00000099(153)

Now you do it with XOR and tell me which one is easier..

[oler1s]

im also not seeing the big picture really. How do i convert a 24bits, to 16bits?

If I said, you have 2, 2, and want 4. What would you do with 2 and 2? You would say, just add them. It's dead obvious.

Now, converting 24bits to 16bits requires a number of mathematical operations as well. Obviously, it's a bit more involved than 2+2, but surprisingly not all that much. It's pretty straightforward , and we want you to be able to see how to put together the mathematical operations.

I mean, we could give you the answer. But then all someone has to do is give you RGBA to ARGB or something simplistic, with just a few things changed around. And you'll still be clueless.