Char Comparison Logic error

[chazzy69]

Hello i seem to have trouble with comparing two chars

e.g.
This works if

(char == 'z')

but when i try if

(char != 'z')

it always returns false.

Heres the actual line of code-

while (var_name !=('a' || 'b' || 'c' || 'd' || 'e' || 'f'')  ) {
code goes here
}

The problem is that even if var_name is equal to one of those values it loops infinitley.

Any help in this matter is greatly appreciated

[chazzy69]

Actually i did some more checking it seems rather to be a error with the or statement -

var_name !=('a' || 'A');

but

var_name !=('a');

works

[chazzy69]

No need to reply i have got around the problem,

by using an if flag within the a while statement,

Thanks anyways

[Banfa]

('a' || 'A') will have the value 1, || is a logical OR and outputs 0 or 1. It only outputs 0 if both sides of the operand are 0 so ('a' || 'A') = 1.

Therefore

var_name !=('a' || 'A')

is equivalent to

var_name != 1

which is, I suspect, not what you wanted. To test to see if var_name is not 'a' and not 'A' you need this expression

var_name != 'a' && var_name != 'A'