Print number of times an input was given, and take the average of the inputs

[vileoxidation]

Hello, and thanks for any help in advance!

Basically, as the title says, I am looking for a way to print the number of times the user gave the program an input, and then also print the average of all the inputs.

So far, I have initialized three variables as follows:

int counter=0;
int sum=0;
float average=0;

Do I need to use a loop to do this? I have also written the expressions for the three variables:

sum = sum + size;
counter = counter + 1;
average = sum/counter;

I have tried printing the values of counter and average, and I get a negative counter value and a nonense average value.

So, in summary, do I need a loop to print the number of inputs and their average? Also, using a loop or not, how do I get the second three lines of code to work correctly?

Thank you in advance for any help!!

[whodgson]

Yes you need to declare size and since you are keeping track of sum, count and average you need to control with a loop. You also need to input something with cin>>.At the moment the three variable = 0 and you are also dividing by 0

[vileoxidation]

I already have declared size, and have an input already set for size, and the program, which prints squares, works perfectly except for this part. I just didn't want to post too much code.

But how do I actually set up the loop using them? That is the problem I am having.

[whodgson]

You could do something like this:
[CODE=cpp]
cout<<"Enter an integer";
for(int i=0;i<20;i++)
{cin>>integer;
numberIntegersE ntered+=1;
sum+=integer;
averageSum=sum / numberIntegersE ntered;
cout<<"The average of the integers entered is: "<<averageSum<< endl;
//if this was a function you could add:
return numberIntegersE ntered;//and display this value
[/CODE]