How to print vector element address ?

[mmk]

Hi,

Anyone can suggest me how to print vector element address in c++.

Thank you,
Murali

[gpraghuram]

Hi,

Anyone can suggest me how to print vector element address in c++.

Thank you,
Murali

You can print the address using the & operator and the index
[code=cpp]
vector<int> v1;

cout<<&v1[0]<<endl;
[/code]

This will get u the address

Raghuram

[mmk]

You can print the address using the & operator and the index
[code=cpp]
vector<int> v1;

cout<<&v1[0]<<endl;
[/code]

This will get u the address

Raghuram

Dear raghu, i tried about what you have suggested. But, still I am facing the problem. Please suggest me how to resolve this.

[code=cpp]
// vector::begin
#include <iostream>
#include <vector>
using namespace std;

int main ()
{
vector<int> myvector;

// Fill vector with 1 to 5 ... 3 times
for (int i=1; i<=5; i++) myvector.push_b ack(i);
for (int i=1; i<=5; i++) myvector.push_b ack(i);
for (int i=1; i<=5; i++) myvector.push_b ack(i);

vector<int>::it erator it;

cout << "Your vector contains contains:";
for ( it=myvector.beg in() ; it < myvector.end(); it++ )
cout << " " << *it;
cout << endl;

for( it = myvector.begin( ); it != myvector.end(); )
{
if( *it == 5 )
{
cout << "Erasing" << *it << endl;
cout << "Address of it is " << &myvector[it] << endl;
myvector.erase( it);
}
else
{
cout << "Incrementi ng it " << *it << endl;
cout << "Address of it is " << &myvector[it] << endl;
++it;
}
}
cout << "After erasing all 5s it is pointing to" << *it << endl;

cout << "Final Vector list contains:";
for ( it=myvector.beg in() ; it < myvector.end(); it++ )
cout << " " << *it;
cout << endl;

return 0;
}

[/code]

In above code while trying to print the address of &myvector[it] (with iterator is giving an error message.

Please suggest me

[MooX]

Hi gpraghuram,


[code=cpp]
vector<int>::it erator it
[/code]

it is pointer

[code=cpp]
&myvector[*it]
[/code]

will work.

:)

[Ganon11]

However, *it will only give you a number between 1 and 4, so you will get the addresses of the second through fourth element of the vector repeatedly. Your problem is you are trying to mix iterator access with array-index-like access, which shouldn't be done. If you want to print the addresses of the vector element, you should use for loops:

[CODE=cpp]for (int i = 0; i < myvector.size() ; i++) {
cout << "Address of " << i << "th element is " << &myvector[i] << endl;
}[/CODE]

[mmk]

Hi gpraghuram,


[code=cpp]
vector<int>::it erator it
[/code]

it is pointer

[code=cpp]
&myvector[*it]
[/code]

will work.

:)

Hi Moox,

This worked fine for me.

Thank you and all who responded for my query.

Cheers,
Mmk

[mmk]

However, *it will only give you a number between 1 and 4, so you will get the addresses of the second through fourth element of the vector repeatedly. Your problem is you are trying to mix iterator access with array-index-like access, which shouldn't be done. If you want to print the addresses of the vector element, you should use for loops:

[CODE=cpp]for (int i = 0; i < myvector.size() ; i++) {
cout << "Address of " << i << "th element is " << &myvector[i] << endl;
}[/CODE]

Dear Ganon11,

myvector is a vector object. As i know there is no size() member function in c++ concept. If I am wrong please correct me.

Cheers,
MMk

[Laharl]

There is a size() member function in nearly every STL object. If you don't believe me, Google them and check.

[Ganon11]

Dear Ganon11,

myvector is a vector object. As i know there is no size() member function in c++ concept. If I am wrong please correct me.

Cheers,
MMk

Laharl is correct. .