default template

[kvnil]

Let's say I have a template

template<int S = 4096>
struct A {
....
}

why can't be used as just A? For example, see the following program (which
doesn't compile because "A" is used instead, of A<10>, for instance):

template <int S=4096struct A { enum {size = S}; };

int main(int argc, char* argv[]) {
printf("%d\n",A ::size);
}

Thanks, Kev

[White Wolf]

Re: default template

"kvnil" <kvnil@mail.ruw rote:

Let's say I have a template
>
template<int S = 4096>
struct A {
...
}
>
why can't be used as just A? For example, see the following program (which
doesn't compile because "A" is used instead, of A<10>, for instance):
>
template <int S=4096struct A { enum {size = S}; };
>
int main(int argc, char* argv[]) {
printf("%d\n",A ::size);
}

A template instance's name always have to have those angle brackets. I may
write now something completely stupid (I have never needed a template with
all params defaulted), but I think that the instance of that template should
be called: A<>, so your expression is A<>::size...

Attila