Problem with pointers and string array. C.

[Cheer]

Hello, could anyone help me with C language a little. I'm trying to write a program with pointers, which would scan some words to the array of strings and would print them on a screen. I'm new to C programming, that's why it's so difficult to deal with such a simple task

[code=c]
#include <stdio.h>
#include <string.h>

int main ()
{
char* string[3];
int j;
for(j=0;j<3;j++ )
{

fgets(string[j], sizeof string[j], stdin);

}

for(j=0;j<3;j++ )
{
printf("String number %d: \"%s\"\n", j, string[j]);
}
return 0;
} [/code]

[debasisdas]

Question moved to C / C++ Forum.

[davidcollins001]

Hello, could anyone help me with C language a little. I'm trying to write a program with pointers, which would scan some words to the array of strings and would print them on a screen. I'm new to C programming, that's why it's so difficult to deal with such a simple task

If you are going to declare a 2D array of strings you need to allocate memory for the string (using malloc) otherwise everytime you read a string with fgets it will be overwritten.

You cannot tell fgets the length of the string that it will get before it gets it. If you allocate a suitable size string then use the same length with fgets it will read no
more than that.

You may want to replace the second last character (\n) too ;)

[code=c]
#include <stdio.h>
#include <string.h>

int main ()
{
char* string[3];
int j;
for(j=0;j<3;j++ )
{
string[j] = (char *)malloc(BUFSIZ );
fgets(string[j], sizeof BUFSIZ, stdin);

}

for(j=0;j<3;j++ )
{
printf("String number %d: \"%s\"\n", j, string[j]);
}
return 0;
} [/code]