a problem with the validty of my tax program

[zero9899]

ok not sure how to accomplish my goal but's it's simple i want the program to ask if 125 was the correct amount entered but im not sure what is the simplest way to accomplish that i cant seem to get while and if to work. the program hangs on the if i know where the chack should go in the codde but i cant figre it out any suggestions would be helpful






/code
#include <stdio.h>
int main (void)
{

float Tax[3]={7.25, 7.5, 7.75}; //this float is the number that are used for the tax wiht the differnt places

float A = 0.0f; // this is the price of the item that will be used to find tax

int B = 0; // this is will pick the data that will be muiltply the tax
char ANS = ' ' ;


printf("Enter price of item: "); // this will be disply on the screen

scanf("%f", &A ); // this is where the price will be assigned to the a value

printf( "You enter %.2f, correct?\n" ,A) ;

scanf ("%s", ANS);


printf("Stores: (1) Delmar, (2) Encintas, (3) La Jolla? "); // this denots what tax percentage will be used

while ((B < 1) || (B > 3))
{ //this is to set the number and display the enter number
scanf("%i", &B ); //u
if ((B < 1) || (B > 3))
printf (" Enter the number associated to the store: "); //this message will appear until a number will be pressed
} // while
printf("The sales tax is %.2f" , A*(Tax[B-1]/100)); //


return 0; //

} // main

[gpraghuram]

The problem is in the line where you read a char
[code=c]

//scanf ("%s", ANS); change this to
scanf ("%s", &ANS);

[/code]

Raghuram

[weaknessforcats]

Generally, you cannot use operators like ==, !=, >, <, <=, >=, etc wth floating point numbers.
Due to the automatic rounding, these operators may report a condition as true when the numbers
are only close in value.

Google for Floating Point Arithmetic or read IEEE 754 standard specification for details.

To compare two floating point numbers, you have to establish a sigma error tolerance.

if (fabs(i - j) < 0.000001) { ... // almost equal }