loop until two doubles differ by 0.00001

[yogi_bear_79]

I am working on divide-and-average lab. I everything done excep the
syntax for the loop. The loop should run replaceing x with the resutls
of (x + a/x )/2 until x, and (x + a/x )/2 differ by no more than a
given amout, for example 0.00001. I've tried various ideas, the
closest I came was while(x - divavg(a, x) != 0), which more or les
sworked. It stoppend the loop when x = (x + a/x )/2, but I'm not sure
that exactly meets the goal.

[hurcan solter]

Re: loop until two doubles differ by 0.00001

On Mar 11, 3:40 am, yogi_bear_79 <yogi_bear...@y ahoo.comwrote:

I am working on divide-and-average lab. I everything done excep the
syntax for the loop. The loop should run replaceing x with the resutls
of (x + a/x )/2 until x, and (x + a/x )/2 differ by no more than a
given amout, for example 0.00001. I've tried various ideas, the
closest I came was while(x - divavg(a, x) != 0), which more or les
sworked. It stoppend the loop when x = (x + a/x )/2, but I'm not sure
that exactly meets the goal.

something like,

fabs(x-divavg(a,x)) < 0.00001;

and make it a function

[yogi_bear_79]

Re: loop until two doubles differ by 0.00001

On Mar 10, 10:16 pm, hurcan solter <hsol...@gmail. comwrote:

On Mar 11, 3:40 am, yogi_bear_79 <yogi_bear...@y ahoo.comwrote:
>

I am working on divide-and-average lab.  I everything done excep the
syntax for the loop. The loop should run replaceing x with the resutls
of (x + a/x )/2 until x,  and (x + a/x )/2 differ by no more than a
given amout, for example 0.00001.  I've tried various ideas, the
closest I came was while(x - divavg(a, x)  != 0), which more or les
sworked. It stoppend the loop when x =  (x + a/x )/2, but I'm not sure
that exactly meets the goal.

>
something like,
>
 fabs(x-divavg(a,x)) < 0.00001;
>
and make it a function

Thanks, while(fabs(x-divavg(a, x)) 0.00001) works fine, except it
stops one short, I've also tried a do/while same results, any syntax I
am missing so I don't have to put one more cout statement outside the
loop to catch the last iteration.