template member function

[Alexander Stippler]

Hey all,

what exactly is forbidden/wrong with the following call of a template
member function;

template <typename T>
struct Base
{
template <int N>
void
cio();
};

template <typename T>
struct Derived
: public Base<T>
{
template <int N>
void
cio()
{
Base<T>::cio<N> (); // !!!!!! <--- what's the
problem here?
}
};

int
main()
{
}

Best regards,
Alex

[Sam]

Re: template member function

Alexander Stippler writes:

Hey all,
>
what exactly is forbidden/wrong with the following call of a template
member function;
>
template <typename T>
struct Base
{
template <int N>
void
cio();
};
>
template <typename T>
struct Derived
: public Base<T>
{
template <int N>
void
cio()
{
Base<T>::cio<N> (); // !!!!!! <--- what's the
problem here?
}
};
>
int
main()
{
}

Sometimes the parsing rules, when templates are involved, get a bit hairy
and what might seem obvious to a meatbag, is not so obvious to a mechanical
parser, to you have to give the compiler a bit of help. Rewriting the
offending statement as:

Base<T*b=static _cast<Base<T*>( this);

b->cio<N>();

This should do what you want.


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[witmer]

Re: template member function

On Mar 9, 12:27 pm, Alexander Stippler <alexander.stip p...@uni-ulm.de>
wrote:

Hey all,
>
what exactly is forbidden/wrong with the following call of a template
member function;
>
template <typename T>
struct Base
{
    template <int N>
        void
        cio();
>
};
>
template <typename T>
struct Derived
    : public Base<T>
{
    template <int N>
        void
        cio()
        {
            Base<T>::cio<N> ();           // !!!!!!  <---   what's the
problem here?
        }
>
};
>
int
main()
{
>
}

The parser doesn't know that cio is a template.
Try:

Base<T>::templa te cio<N>();

[Alexander Stippler]

Re: template member function

On 2008-03-09 18:44:34 +0100, Sam <sam@email-scan.comsaid:

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>
Alexander Stippler writes:
>

>Hey all,
>>
>what exactly is forbidden/wrong with the following call of a template
>member function;
>>
>template <typename T>
>struct Base
>{
>template <int N>
>void
>cio();
>};
>>
>template <typename T>
>struct Derived
>: public Base<T>
>{
>template <int N>
>void
>cio()
>{
>Base<T>::cio<N >(); // !!!!!! <--- what's the
>problem here?
>}
>};
>>
>int
>main()
>{
>}

>
Sometimes the parsing rules, when templates are involved, get a bit hairy
and what might seem obvious to a meatbag, is not so obvious to a mechanical
parser, to you have to give the compiler a bit of help. Rewriting the
offending statement as:
>
Base<T*b=static _cast<Base<T*>( this);
>
b->cio<N>();
>
This should do what you want.
>
>
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Content-Transfer-Encoding: 7bit
>
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>
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3uV5MPry+XjrQfJ e5t7mAFU=
=9V16
-----END PGP SIGNATURE-----
>
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Thanks a lot. It should have been obvious to me. I even knew your
solution long time ago :-(