Templated typedefs

[Juha Nieminen]

Apparently something like this is not currently possible:

template<typena me T>
typedef bool(*VectComp) (const std::vector<T>& , const std::vector<T>& );

void foo(VectComp<in t>);

template<typena me T>
void bar(VectComp<T> );

Will this be possible in the next C++ standard?

[Michael DOUBEZ]

Re: Templated typedefs

Juha Nieminen a écrit :

Apparently something like this is not currently possible:
>
template<typena me T>
typedef bool(*VectComp) (const std::vector<T>& , const std::vector<T>& );

No. template oftypedef are not allowed.
Current usage is:

template<typena me T>
struct VectComp
{
typedef bool(*type)(con st std::vector<T>& , const std::vector<T>& );
};

>
void foo(VectComp<in t>);

void foo(VectComp<in t>::type);

>
template<typena me T>
void bar(VectComp<T> );

template<typena me T>
void bar(typename VectComp<T>::ty pe);

>
Will this be possible in the next C++ standard?

AFAIK not under this form, it will use aliasing.
See: http://www.artima.com/cppsource/cpp0x.html

Michael