Call up functions

[masterofthebus]

Hi everyone,

I have a question that is tricking me.

I need to do something like this:
-----------------------------------------------------------

int a;


void* function(const &function){
    //execute the code of the function here that i sent the address
}

int main(){
       a = 0 ;

       call(&myFunction);

    cout << a ;
}

----------------------

I don't know if i explained it well but what I need is a function to call another functions by its adress. For example, I use call(&function2 ); then it runs all function2()

.

[weaknessforcats]

You need a function pointer.

That is, your call() needs an argument that is a pointer to a function that has the correct arguments and return type.
[code=cpp]
void AFunction(int x, float y)
{
//etc...
{
[/code]
A pointer to this function would be:
[code=cpp]
void (*fp)(int, float);
[/code]

Then you can assign the address of AFunction to this pointer:
[code=cpp]
fp = AFunction;
[/code]

The name of a function is the address of the function so you not code &AFunction.

Then, your call() just has to have a function pointer argument:
[code=cpp]
void call(void (*fp)(int, float))
{
//etc...
}
[/code]

Finally, in main() you can make the call:
[code=cpp]
call(AFunction) ;
[/code]

Remember, the argments and return type declared in your function pointer must match those of the actual function or you cannot put that function's address into the pointer.