operator+ , Linked list

[APEJMAN]

I have two linked list and I want to Concatenates these two linked lists, placing the elements of the second list after the elements of the first list. For example, if list1={1,2,3} and list2={4,5,6} then calling:

list3 = list1 + list2;
would result in list3={1,2,3,4, 5,6}.

so I want to define operator+ for these linked list
any idea how I can do this?

[Ganon11]

You would override

[CODE=cpp]List& List::operator+ (const List& rightHandSide);[/CODE]

with the appropriate code.

Now, how can you get the last element of the List to point to the first element of rightHandSide?

[APEJMAN]

You would override

[CODE=cpp]List& List::operator+ (const List& rightHandSide);[/CODE]

with the appropriate code.

Now, how can you get the last element of the List to point to the first element of rightHandSide?

I am confused
I dont know

[APEJMAN]

Operator + Linked LIst

Lets say I have

//Operator + , concatenates two linked lists
template <typename T>
LinkedList<T>& LinkedList<T>:: operator+ (const LinkedList<T>& right)
{

}

I am trying to write the + operator so that I can add two linked list together like
list3=list1+lis t2;

any idea?
Thanks

[Laharl]

Think about it in terms of moving the pointers in the list. Which pointer(s) would need to be moved?

EDIT: Please don't post two threads on the same topic.

[APEJMAN]

we dont need to move any thing
just to make this work
link3=link1+lin k2

the declaration for the link list is:
Node<T>* newNode=new Node<T>(value)

any idea?
thanks

[Ganon11]

How are you confused? With which part? To help you, we need a little more description than "I don't know."

[Ganon11]

As Laharl said, please don't make two threads on the same topic. It doesn't help you get your help faster, it only makes things very confusing for the people trying to help you - thus causing them not to want to help. In short, you only need one thread for your topic.

[APEJMAN]

I fixed it
here is the code
this can add 2 linked list to gether

template <typename T>
LinkedList<T> LinkedList<T>:: operator+ (const LinkedList<T>& right)
{
LinkedList result(*this);
for (int i=0 ; i<right.size() ; i++)
result.push_bac k(right[i]);
return result;
}