getting the size of dynamic array

[abdulsamad]

Hello there
i wanna get the the size of a dynamic array of integer type which i have created like that.........

[CODE=cpp] int *arr=0;
arr = createTempArray ();
arr = storeRowValues( arr);
arr = storeColValues( arr);
check(arr);
}
}
}
int* createTempArray ()
{
int length = rowIndex+colInd ex;
int *tempArray = new int[length];
return tempArray;
}
int *storeRowValues (int *tempArr)
{
for(int i=0;i < colIndex; ++i)
{
tempArr[i]=array[rowIndex][i];
}
return tempArr;
}
int *storeColValues (int *tempArr)
{
int size = sizeof(tempArr) / sizeof(tempArr[0]);

for(int i=0; i < size; i++)
{ if(tempArr[i]==7)
{
--i;
break;
}
}[/CODE]


I wanna get the the value of size in

storeColValues( int *tempArr) method ..............

**********code* **********
[CODE=cpp]int size = sizeof(tempArr) / sizeof(tempArr[0]);[/CODE]

this line always gives me a result of 1



somebody please help me and give me some hint or piece of code so that i can find the size correctly...... ..

[Ganon11]

When you pass an array (or pointer to an array) to a function, the function doesn't know for certain if it is an array or not - it just gets an address. It assumes this address is pointing to 1 - and only 1 - element. Thus, the sizeof(array) call returns the size of that pointer, not the size of the entire array.

The only way for a function to know the size of an array is to pass the length as an argument, or use the length as a global constant variable.

[Studlyami]

In visual c++ you can use the _msize() to get the size of the dynamic array. This is not a standard c++ function so it is not portable. Other than that you are stuck with having to create a variable for the array size.