expected `;' before "it"

[curious2007]

Hello,

In a template implementation, I am trying to define a list iterator using the following line:

list<AI>::const _iterator it;

However, I get the following error:

expected `;' before "it"

I have included #include <list>
and using namespace std at the beginning of my code. But the problem did not go away. I would apprecate any insight. Thanks.

[weaknessforcats]

You forgot to #include <list>.

[curious2007]

no, I have #include<list>
but I still get this error.

[Benny the Guard]

Are you using:

using namespace std;

If not try the following in your declaration.

std::list

[curious2007]

Sorry for not writing it clearly but as can be seen from my inital post, I have

#include<list>
using namespace std;

at the beginning of my code. But to no avail, I am still getting the error.

[Meetee]

Hello,

In a template implementation, I am trying to define a list iterator using the following line:

list<AI>::const _iterator it;

However, I get the following error:

expected `;' before "it"

I have included #include <list>
and using namespace std at the beginning of my code. But the problem did not go away. I would apprecate any insight. Thanks.

Try this:

typedef typename list<AI>::const _iterator observerIterato r;
observerIterato r it;

OR

typename list<AI>::const _iterator it;

It may help..!

Regards

[weaknessforcats]

This compiles and links with Visual Studio.NET 2005
[code=cpp]
#include <iostream>
using namespace std;
#include <list>
class AI
{

};
int main()
{
list<AI>::const _iterator it;
}
[/code]

[curious2007]

Thanks,

typename list<AI>::const _iterator it;

did the trick.

I am still not familiar with the subtleties of these but weaknessforcats , somehow your post#7 seems to me a different thing. Because in your example you already declare and define a class AI. So computer has no problem, recognizinf list<AI>. Whereas when AI is going to be determined when a template is initiated we are having additional problems when we write list<AI>.

[weaknessforcats]

I am still not familiar with the subtleties of these but weaknessforcats , somehow your post#7 seems to me a different thing. Because in your example you already declare and define a class AI. So computer has no problem, recognizinf list<AI>. Whereas when AI is going to be determined when a template is initiated we are having additional problems when we write list<AI>.

The originakl problem was that:

list<AI>::const _iterator it;

was not compiling.

This looks like you want to create an const iterator object, it, for a list<AI>. You know, so you can:
[code=cpp]
list<AI> mylist;
list<AI>::const _iterator it = mylist.begin();
[/code]

That is what my post #7 was about.

This:
[code=cpp]
typename list<AI>::const _iterator it;
[/code]

only works if it is inside a template. You can't use typename outside a template. The original problem said nothing about the code being inside a template.